Apologies if I’m just rehashing questions and answers that already exists in likely multiple threads but I’d like to understand the roll / balance of aperture, focal length, resolution a little better.
Assume I have a 5” refractor that has a fl of 900mm and an f-ratio of f/7.0. With a 3.8 micron camera that’ll give me an image scale of 3.8/(900/206) = 0.87”/px.
Now assume I also have a 10” reflector with a central obstruction of 30%. With a reducer I can get this down to let’s say 1800mm at f/7.0 (rounding numbers to keep them the same). So if I bin the same camera at 2x2 I get the same image scale of 0.87”/px. That means I’ll have the exact same resolution as the refractor. So there’s no win but….am I right in saying that the reflector will gather light ((10/2)^2 * 0.7 / (5/2)^2) = 2.8 times faster than the refractor . So although I’m not gaining on resolution (and loosing on FoV) I’m getting a much improved SNR (2.8 / sqrt(2.8) = 1.67 times) for the same exposure time by using the reflector.
Tom.